In a school’s laboratory, students require 50.0 ml of 2.50 m h2so4 for an experiment, but the only available stock solution of the acid has a concentration of 18.0 m. what volume of the stock solution would they use to make the required solution? use mc018-1.jpg. 0.900 ml 1.11 ml 6.94 ml 7.20 ml

Answers

  • Réponse publiée par: pauyonlor

    Hello!

    In a school’s laboratory, students require 50.0 mL of 2.50 M H2SO4 for an experiment, but the only available stock solution of the acid has a concentration of 18.0 M. What volume of the stock solution would they use to make the required solution?  

    0.900 mL  

    1.11 mL  

    6.94 mL  

    7.20 mL

    We have the following data:

    M1 (initial molarity) = 2.50 M (or mol/L)

    V1 (initial volume) = 50.0 mL → 0.05 L

    M2 (final molarity) = 18.0 M (or mol/L)

    V2 (final volume) = ? (in mL)

    Let's use the formula of dilution and molarity, so we have:

    M_{1} * V_{1} = M_{2} * V_{2}

    2.50 * 0.05 = 18.0 * V_{2}

    0.125 = 18.0\:V_2

    18.0\:V_2 = 0.125

    V_2 = \dfrac{0.125}{18.0}

    V_2 \approx 0.00694\:L \to \boxed{\boxed{V_2 \approx 6.94\:mL}}\:\:\:\:\:\:\bf\green{\checkmark}

    The volume is approximately 6.94 mL

    _______________________________

    \bf\green{I\:Hope\:this\:helps,\:greetings ...\:Dexteright02!}\:\:\ddot{\smile}

  • Réponse publiée par: meteor13

    The volume of stock solution of acid required 6.94 mL.

    Explanation:

    To calculate the volume of stock solution, we use the equation given by neutralization reaction:

    M_1V_1=M_2V_2

    where,

    M_1\text{ and }V_1 are the molarity and volume of acid which is H_2SO_4

    M_2\text{ and }V_2 are the molarity and volume of stock solution of acid.

    We are given:

    M_1=2.50M\\V_1=50.0mL\\M_2=18.0M\\V_2=?

    Putting values in above equation, we get:

    2.50M\times 50.0mL=18.0M\times V_2\\\\V_2=6.94mL

    Hence, the volume of stock solution of acid required 6.94 mL.

  • Réponse publiée par: meteor13

    Hello!

    In a school’s laboratory, students require 50.0 mL of 2.50 M H2SO4 for an experiment, but the only available stock solution of the acid has a concentration of 18.0 M. What volume of the stock solution would they use to make the required solution?  

    0.900 mL  

    1.11 mL  

    6.94 mL  

    7.20 mL

    We have the following data:

    M1 (initial molarity) = 2.50 M (or mol/L)

    V1 (initial volume) = 50.0 mL → 0.05 L

    M2 (final molarity) = 18.0 M (or mol/L)

    V2 (final volume) = ? (in mL)

    Let's use the formula of dilution and molarity, so we have:

    M_{1} * V_{1} = M_{2} * V_{2}

    2.50 * 0.05 = 18.0 * V_{2}

    0.125 = 18.0\:V_2

    18.0\:V_2 = 0.125

    V_2 = \dfrac{0.125}{18.0}

    V_2 \approx 0.00694\:L \to \boxed{\boxed{V_2 \approx 6.94\:mL}}\:\:\:\:\:\:\bf\green{\checkmark}

    The volume is approximately 6.94 mL

    _______________________________

    \bf\green{I\:Hope\:this\:helps,\:greetings ...\:Dexteright02!}\:\:\ddot{\smile}

  • Réponse publiée par: elaineeee

    answer:

    Make More Than Just Soups

    Chicken stock or broth can be used for all sorts of delicious dishes, not just soups and stews. From a cooking liquid for grains like rice and quinoa to a braising liquid for chicken or vegetables, it's a very useful ingredient that brings extra flavor to a recipe.

    Explanation:

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  • Réponse publiée par: JUMAIRAHtheOTAKU

    Hindi ko Po maintindihan

    Explanation:

    pakiulit

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In a school’s laboratory, students require 50.0 ml of 2.50 m h2so4 for an experiment, but the only a...