Calculate the number of moles of solute present in the
es of solute present in the following solutions:
a. 1.25 l of 4.28 m hcl
b. 85.3 g of aqueous solution that is 2.47 percent sucrose
Answers: 1
answer:
a. 195.06 g
b. 2.11
elaborate your question on letter b, i've got the answer on that one by using the formula of percent weight by weight (%w/w)
%w/w = weight solute/weight volume
a. 5.35 moles of solute
b.0.00616 mol sucrose
Explanation:
a.)
step 1: list all given variables
Volume = 1.25 L
Molarity = 4.28 M
Step 2: calculate the unknown
Molarity= mole of solute/Liter of solution
Mole of solute = molarity x liter of solution
= 4.28 M x 1.25 L
= 5.35 moles of solute
b.)
step 1: list all given variables
mass of solution = 85.3 g
mass % sucrose = 2.47 %
step 2: calculate the unknown
2.47%×1/100×85.3g×(1 mol sucrose)/(342.2965 grams sucrose)=0.00616 mol sucrose
answer:
Totok man
I hOPE iT wILL help
Explanation:
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