Which set of quantum numbers corresponds to the fourth electron in a 3p orbital?
a. 3, 1, 0, +1/2
b. 3, 1, 0, -1/2
c. 3, 1, 1, +1/2
d. 3, 1, -1, -1/2

Answers

  • Réponse publiée par: tayis

    correct answer is d

    Explanation:


    Which set of quantum numbers corresponds to the fourth electron in a 3p orbital?  a. 3, 1, 0, +1/2 b
  • Réponse publiée par: abyzwlye

    answer:

    B.O

    Explanation:

    hinde po ako sigurado sorry po

  • Réponse publiée par: sherelyn0013

    answer:

    Carbon and it's compound

    Explanation:

    Group 4A (or IVA) of the periodic table includes the nonmetal carbon (C), the metalloids silicon (Si) and germanium (Ge), the metals tin (Sn) and lead (Pb), and the yet-unnamed artificially-produced element ununquadium (Uuq).

    The Group 4A elements have four valence electrons in their highest-energy orbitals (ns2np2). Carbon and silicon can form ionic compounds by gaining four electrons, forming the carbide anion (C4-) and silicide anion (Si4-), but they more frequently form compounds through covalent bonding

  • Réponse publiée par: sicienth

    answer:

    Carbon(C)

    Explanation:

     as a group 14 element, has four electrons in its outer shell. Carbon typically shares electrons to achieve a complete valence shell, forming bonds with multiple other atoms.

  • Réponse publiée par: Laurenjayshree

    answer:

    Carbon

    Explanation:

    Carbon (C), as a group 14 element, has four electrons in its outer shell.

  • Réponse publiée par: sicienth

    answer:

    Sn(BrO4)4

    Explanation:

    The chemical formula of perbromate is (BrO4)-

    The chemical formula for tin that loses four electrons is Sn4+

  • Réponse publiée par: villatura

    Hello!

    Select all of the statements that are true.  

    Each orbit holds a fixed number of electrons.

    The n = 1 orbit can only hold two electrons.

    Each orbit can hold an unlimited number of electrons.

    Each orbit is limited to a maximum of four electrons.

    Solving:

    We have the following sub levels (s,p,d,f) and orbitals (each orbital receives at most two electrons).

    sub-level s = 0 (has 1 orbital)  \underbrace{\boxed{\uparrow\:\downarrow}}_0}

    sub-level p = 1 (has 3 orbitals)  \underbrace{\boxed{\uparrow\:\downarrow}}_{-1}}\underbrace{\boxed{\uparrow\:\downarrow}}_0}\underbrace{\boxed{\uparrow\:\downarrow}}_{+1}}

    sub-level d = 2 (has 5 orbitals)  \underbrace{\boxed{\uparrow\:\downarrow}}_{-2}}\underbrace{\boxed{\uparrow\:\downarrow}}_{-1}}\underbrace{\boxed{\uparrow\:\downarrow}}_0}\underbrace{\boxed{\uparrow\:\downarrow}}_{+1}}\underbrace{\boxed{\uparrow\:\downarrow}}_{+2}}

    sub-level f = 3 (has 7 orbitals)   \underbrace{\boxed{\uparrow\:\downarrow}}_{-3}}\underbrace{\boxed{\uparrow\:\downarrow}}_{-2}}\underbrace{\boxed{\uparrow\:\downarrow}}_{-1}}\underbrace{\boxed{\uparrow\:\downarrow}}_0}\underbrace{\boxed{\uparrow\:\downarrow}}_{+1}}\underbrace{\boxed{\uparrow\:\downarrow}}_{+2}}\underbrace{\boxed{\uparrow\:\downarrow}}_{+3}}

    Each sub-level accommodates 2 to 14 electrons, but it is known that each sub-level has a number of orbits and that each orbital can accommodate a maximum of 2 electrons

    Now, If for n = 1, we only can have:

    1s¹  \underbrace{\boxed{\uparrow\:\:\:}}_0}

    or

    1s²   \underbrace{\boxed{\uparrow\:\downarrow}}_0}

    Soon:

    1- (TRUE) Each orbit holds a fixed number of electrons.

    2- (TRUE) The n = 1 orbit can only hold two electrons.

    3- (FALSE) Each orbit can hold an "unlimited" number of electrons.

    limited (one or two electrons)

    4- (FALSE) Each orbit is limited to a maximum of "four" electrons.

    maximum (two electrons)

    The statements 1 and 2 are true

    ________________________

    \bf\blue{I\:Hope\:this\:helps,\:greetings ...\:Dexteright02!}\:\:\ddot{\smile}

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Which set of quantum numbers corresponds to the fourth electron in a 3p orbital? a. 3, 1, 0, +1/2 b...