Réponse publiée par: Graknameanswer:a part of fish po ataExplanation:di q po sure pero sana makatulong

Réponse publiée par: kelly072a. 5.35 moles of soluteb.0.00616 mol sucroseExplanation:a.) step 1: list all given variables Volume = 1.25 L Molarity = 4.28 M Step 2: calculate the unknown Molarity= mole of solute/Liter of solution Mole of solute = molarity x liter of solution = 4.28 M x 1.25 L = 5.35 moles of solute b.) step 1: list all given variables mass of solution = 85.3 g mass % sucrose = 2.47 % step 2: calculate the unknown 2.47%×1/100×85.3g×(1 mol sucrose)/(342.2965 grams sucrose)=0.00616 mol sucrose

answer:

a part of fish po ata

Explanation:

di q po sure pero sana makatulong

a. 5.35 moles of solute

b.0.00616 mol sucrose

Explanation:

a.)

step 1: list all given variables

Volume = 1.25 L

Molarity = 4.28 M

Step 2: calculate the unknown

Molarity= mole of solute/Liter of solution

Mole of solute = molarity x liter of solution

= 4.28 M x 1.25 L

= 5.35 moles of solute

b.)

step 1: list all given variables

mass of solution = 85.3 g

mass % sucrose = 2.47 %

step 2: calculate the unknown

2.47%×1/100×85.3g×(1 mol sucrose)/(342.2965 grams sucrose)=0.00616 mol sucrose

c.sulfur

Explanation: