# Father has a collection of old coins. he ha an equal amount of 10-centavo coins and 25-centavo coins. the total amount of coins is php10.50. how many coins of each kind are there?

Answers: 1

## Answers

Father has a collection of old coins. he ha an equal amount of 10-centavo coins and 25-centavo coins...

There are 30

Let x be the number of 10centavo and 25centavo(because they have the same number and that is why they also have the same variable to be used).

0.10x + 0.25x = 10.50

0.35x = 10.50

Divide both sides by 0.35 in order to x to be alone.

0.35x ÷ 0.35 = 10.50 ÷ 0.35

x = 30

2 kinds of coin

2 kinds of coin

Step-by-step explanation:

30 ¢10 and ¢25 coins

Step-by-step explanation:

To find the number of coins:

0.10 + 0.25 = 0.35

₱10.50 ÷ 0.35 = 30

To check:

30 × ¢25 = ₱7.50

30 × ¢10 = ₱3.00

₱7.50 + ₱3 = ₱10.50

answer:

30 10-cent and 30-25-cent

step-by-step explanation:

php10.50 is 1050cent

10x+25x=1050

simplify

35x=1050

divide both side by 35

x=30