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What is the remainder when (9x+8x²+7x³++x9) is divided by (x-1)

Answers

  • Réponse publiée par: Axelamat

    We have a degree 1 divisor. With this, we are expecting our remainder must be one degree lower than its divisor.

    Using Remainder Theorem, substitute the value of k (value of x when the divisor is equated to zero) to the divided.

    First, equate x - 1 to zero.

    x - 1 = 0

    x = 1

    Then, substitute x to the given expression.

    9(1) + 8(1)^2 + 7(1)^3 + 6(1)^4 + 5(1)^5 + 4(1)^6 + 3(1)^7 + 2(1)^8 + 1^9

    This simplifies into:

    9 + 8 + 7 + 6 + 5 + 4 +3 +2 +1 = 45

    45 has a degree of zero which is exactly one degree lower than its divisor which is x - 1.

    The remainder is 45

  • Réponse publiée par: kuanjunjunkuan

    answer:

    is it 4 hours?

    step-by-step explanation:

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What is the remainder when (9x+8x²+7x³++x9) is divided by (x-1)...