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Find the value of a+b+c if 673a is divisible by 15,673b is divisible by 7 and 673c is divisible by 33​

Answers

  • Réponse publiée par: abyzwlye

    11

    Step-by-step explanation:

    The divisibility rule of 15 is if the number is divisible by both 5 and 3

    The divisibility rule of 3 is if the sum of all digits is divisible by 3

    The divisibility rule of 5 is if the number ends with 0 and 5

    So 6735 is divisible by 15, so A=5

    Well, I really don't know the divisibility rule of 7

    But, 6734 is divisible by 7, so B=4

    The divisibility rule of 33 is if the number is both divisibile by 3 and 11

    The divisibility rule of 11 is if the alternative digits of the number

    is equal

    So it's, 6732, so C=2

    Add them together,

    5+4=9

    9+2=11

  • Réponse publiée par: danigirl12

    answer: dunno

    step-by-step explanation:

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Find the value of a+b+c if 673a is divisible by 15,673b is divisible by 7 and 673c is divisible by 3...