One square has a side of 3 meters shorter than the side of a second square. the area of the longer square is 4 times, the area of the smaller square. find the length of a side of each square.

Answers

• Réponse publiée par: snow01

  Smaller square has a side of 3 meters while the bigger square has a side of 6 meters.

  Step-by-step explanation:

  Side (s)  of second, bigger square: x

  Side of shorter square: x-3 (shorter by 3 meters than the second square)

  Area = s²  where s is the side

  Area of smaller square = (x-3)²  (where x is the side)

  Area of bigger, second square = x²

  Condition:

  The area of the bigger square is 4 times the area of the smaller square.

  Equation:

  x² = 4(x-3)²

  x²  = 4(x² - 6x + 9)

  x² = 4x² - 24x + 36

  4x² - x² - 24x + 36 = 0

  3x² - 24x + 36 = 0

  3(x² - 8x + 12) = 0

  Factor (x² - 8x + 12) then equate each factor to 0:

  (x - 2) (x - 6) = 0

  x-2= 0

  x = 2

  x - 6 = 0

  x = 6

  Choose the higher value from where 3 meter will be subtracted: x = 6

  Substitute x = 6 to find the length of each side:

  Second, bigger square: x = 6 meters

  Smaller square: x-3 = 6-3 = 3 meters

  Smaller square has a side of 3 meters while the bigger square has a side of 6 meters.

  Check:

  Area of smaller square = (3 meters)² = 9 meters²

  Area of bigger square = (6 meters)² = 36 meters²

  Condition:

  The area of the bigger square is 4 times the area of the smaller square.

  36 = 4(9)

  36 = 36  (True)
• Réponse publiée par: cyrishlayno

  answer:

  hi

  step-by-step explanation:

• Réponse publiée par: janalynmae

  3/8 (3 over eight) is the answer