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One square has a side of 3 meters shorter than the side of a second square. the area of the longer square is 4 times, the area of the smaller square. find the length of a side of each square.

Answers

  • Réponse publiée par: snow01
    Smaller square has a side of 3 meters while the bigger square has a side of 6 meters.

    Step-by-step explanation:

    Side (s)  of second, bigger square: x

    Side of shorter square: x-3 (shorter by 3 meters than the second square)

    Area = s²  where s is the side

    Area of smaller square = (x-3)²  (where x is the side)

    Area of bigger, second square = x²

    Condition:

    The area of the bigger square is 4 times the area of the smaller square.

    Equation:

    x² = 4(x-3)²

    x²  = 4(x² - 6x + 9)

    x² = 4x² - 24x + 36

    4x² - x² - 24x + 36 = 0

    3x² - 24x + 36 = 0

    3(x² - 8x + 12) = 0

    Factor (x² - 8x + 12) then equate each factor to 0:

    (x - 2) (x - 6) = 0

    x-2= 0

    x = 2

    x - 6 = 0

    x = 6

    Choose the higher value from where 3 meter will be subtracted: x = 6

    Substitute x = 6 to find the length of each side:

    Second, bigger square: x = 6 meters

    Smaller square: x-3 = 6-3 = 3 meters

    Smaller square has a side of 3 meters while the bigger square has a side of 6 meters.

    Check:

    Area of smaller square = (3 meters)² = 9 meters²

    Area of bigger square = (6 meters)² = 36 meters²

    Condition:

    The area of the bigger square is 4 times the area of the smaller square.

    36 = 4(9)

    36 = 36  (True)

  • Réponse publiée par: cyrishlayno

    answer:

    hi

    step-by-step explanation:

  • Réponse publiée par: janalynmae
    3/8 (3 over eight) is the answer
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One square has a side of 3 meters shorter than the side of a second square. the area of the longer s...