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Find the equation of the line through (2,4) and (4,6).​

Answers

  • Réponse publiée par: cbohol56

    Hello !!

    Find the inclination.

    m = (yB - yA)/(xB - xA)

    m = (4 - 2)/(6 - 4)

    m = 2/2

    m = 1

    Find the linear coeficient.

    y = mx + n

    4 = 1(2) + n

    4 = 2 + n

    2 + n = 4

    n = 4 - 2

    n = 2

    Reduced equation is y = x + 2

    Find the general equation.

    y = x + 2

    x + 2 = y

    x + 2 - y = 0

    x - y + 2 = 0

    General equation is x - y + 2 = 0

    I hope I have collaborated !

  • Réponse publiée par: kateclaire

    (x,y)

    (2,1)

    (5,-8)

    y

    .

    .

    .

    . .(2,1)

    . . . . 0 . . . . . . . . x

    .

    .

    .

    .

    .

    .

    .

    . .(5-8)

    slope: -3

    y-intercept: (0,7)

  • Réponse publiée par: trizianichole20

    answer: false

    Step-by-step explanation:

    (-2, 3) Hence x0 = -2 , y0 = 3 Putting the values (y – 3) = –4(x – (-2)) (y – 3) = –4(x + 2) y – 3 = – 4x – 8 y + 4x – 3 + 8 = 0 y + 4x + 5 = 0 Hence,

    the required equation is y + 4x + 5 = 0

    i hope it helps po

  • Réponse publiée par: maledabacuetes

    Step-by-step explanation:

    1. True

    2. True

    3. True

    4. false

    5. false

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Find the equation of the line through (2,4) and (4,6).​...