Find the equation of the line through (2,4) and (4,6).​

Answers

• Réponse publiée par: cbohol56

  Hello !!

  Find the inclination.

  m = (yB - yA)/(xB - xA)

  m = (4 - 2)/(6 - 4)

  m = 2/2

  m = 1

  Find the linear coeficient.

  y = mx + n

  4 = 1(2) + n

  4 = 2 + n

  2 + n = 4

  n = 4 - 2

  n = 2

  Reduced equation is y = x + 2

  Find the general equation.

  y = x + 2

  x + 2 = y

  x + 2 - y = 0

  x - y + 2 = 0

  General equation is x - y + 2 = 0

  I hope I have collaborated !
• Réponse publiée par: kateclaire

  (x,y)

  (2,1)

  (5,-8)

  y

  .

  .

  .

  . .(2,1)

  . . . . 0 . . . . . . . . x

  .

  .

  .

  .

  .

  .

  .

  . .(5-8)

  slope: -3

  y-intercept: (0,7)
• Réponse publiée par: trizianichole20

  answer: false

  Step-by-step explanation:

  (-2, 3) Hence x0 = -2 , y0 = 3 Putting the values (y – 3) = –4(x – (-2)) (y – 3) = –4(x + 2) y – 3 = – 4x – 8 y + 4x – 3 + 8 = 0 y + 4x + 5 = 0 Hence,

  the required equation is y + 4x + 5 = 0

  i hope it helps po
• Réponse publiée par: maledabacuetes

  Step-by-step explanation:

  1. True

  2. True

  3. True

  4. false

  5. false