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# Solve system of linear system and graph 1. y¹ = 5/3 x¹ + 1 y² = 1/3x² - 1 2. y¹ = x¹ + 2 x² = 3 3. y¹ = 4x¹ + 1 y² = x² - 2 4. y¹ = 1/3x¹ + 2 y² = 2x² - 3

• Réponse publiée par: jasminsexy

Activity 3:

covid 19 pandemic started in Wuhan, China

• Réponse publiée par: kelly072

the answer will be ..or the letters are ... A N U W H

• Réponse publiée par: enrica11

x=2 y= 1

Step-by-step explanation:

put this into this type of method

2x + y = 5

x - y = 1

cancel the y and the operation is addition

2x + x = 5 + 1

3x = 6

divide both side by 3

x= 2

then substitute x to get y

2(2) + y = 5

4 + y = 5

transpose

y = 5-4

y = 1

Given : 1.  x+y=10   ,  2x+y=13

​2.  x+y=2   , x−y=4

3.  x−y=3   , 7x−y=−3

4.  4x+y=2  , x−y=3

5.  x−y=10  , 2x+y=13

To Find : Solve for x & y

Solution:

1.

x+y=10   ,

2x+y=13

=> x = 3

y = 7

( 3 , 7)

​2.

x+y=2   ,

x−y=4

=> 2x = 6 => x = 3

y = 1

( 3 , 1)

3.

x−y=3   ,

7x−y=−3

=> 6x = -6

=> x = - 1

=> y = -4

( 1, - 4)

4.

4x+y=2  ,

x−y=3

=> 5x = 5

=> x = 1

y = - 2

( 1 , - 2)

5.

x−y=10  ,

2x+y=13

=> 3x = 23

=> x = 23/3

y = -7/3

0.7x+0.3x=0.5x+6 linear equations in one variable -

Solve the following x+y/xy=5 and x-5/xy=7 -

solve for x and y : x+y/xy=2,xy/=6

• Réponse publiée par: cland123

Given : 1.  x+y=10   ,  2x+y=13

​2.  x+y=2   , x−y=4

3.  x−y=3   , 7x−y=−3

4.  4x+y=2  , x−y=3

5.  x−y=10  , 2x+y=13

To Find : Solve for x & y

Solution:

1.

x+y=10   ,

2x+y=13

=> x = 3

y = 7

( 3 , 7)

​2.

x+y=2   ,

x−y=4

=> 2x = 6 => x = 3

y = 1

( 3 , 1)

3.

x−y=3   ,

7x−y=−3

=> 6x = -6

=> x = - 1

=> y = -4

( 1, - 4)

4.

4x+y=2  ,

x−y=3

=> 5x = 5

=> x = 1

y = - 2

( 1 , - 2)

5.

x−y=10  ,

2x+y=13

=> 3x = 23

=> x = 23/3

y = -7/3

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Solve system of linear system and graph 1. y¹ = 5/3 x¹ + 1 y² = 1/3x² - 1 2. y¹ = x¹ + 2 x² = 3 3. y...