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The four-digit number a55b is divisible by 6 without remainder. what is a and b? ​

Answers

  • Réponse publiée par: cyrishlayno

    answer:

    so many possible answer

    step-by-step explanation:

    if a= 3, or 6, or 9

    b is 2

    3552

    6552

    9552

    if a is 1, or 4, or 7. then b is 4

    1554

    4554

    7554

    if a is 2, or 5, or 8. then b is 6

    2556

    5556

    8556

    if a is 3, or 6, or 9. then b is 4

    3558

    6558

    9558

    the rule is if the number is divisible by 2 or 3 it is divisible by 6

    any even number is divisible by 2

    add all the digit and if its sum must be divisible by 3.

    ex. 9558

    9+5+5+8= 27

    27 is divisible by 3

    not convinced?

    then 2+7=9

    9 is surely divisible by 3.

  • Réponse publiée par: kambalpandesal23

    1001, 1221, 1331, 2816, 3465

    Explanation:

    if you want more just multiply 11 to a 3 digit number. ^_^

  • Réponse publiée par: stacy05

    4444444444444444444444444

  • Réponse publiée par: princessgarcia23

    6000

    6000÷2= 3000

    6000÷3= 2000

    6000÷4= 1500

    6000÷6= 1000

    6(first digit)-0(last digit)=6

  • Réponse publiée par: calmaaprilgrace

    9990

    Step-by-step explanation:

    9990/2=4995

    9990/5=1998

  • Réponse publiée par: brianneaudreyvuy

    999

    Step-by-step explanation:

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  • Réponse publiée par: nelspas422

    answer:

    3.) 1, 000

    Explanation: The common denominator that could be feasibly divided by the numbers 2, 5, and 10 is the number ended with 0. Since what has been asked here is the least 4-digit number then we could conclude that the digit that is belong with the thousands place is 1. And keep on filling the places of hundreds and tens with 0 to justify what was asked for, least 4-digit number.

    FINAL ANSWER: 1, 0 0 0

    4.) 990

    Explanation: Same goes with the statement above. Since the common denominator that is likely to be divisible by 2, 5, and 10. We will fill the ones place with zero (0). In terms of the tens and hundreds places, considered what is being asked. It says that it should be the greatest 3-digit number, thus, think of the greatest number from the timeline (1-9). Therefore, you could conclude that the number 9 should be placed on the respective places of tens and hundreds.

    FINAL ANSWER: 9 9 0

    5.) 60, 70, 80, & 90

    Explanation: The common denominator that are divisible by the numbers 2 and 5 do ended with zero (0). Since, the thing that was asked are numbers between 50 and 100 therefore:

    60, 70, 80, and 90 are the numbers between 50 and 100 that are divisible by 2 and 5.

  • Réponse publiée par: snow01

    answer:

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    Step-by-step explanation:

    "Four digit numbers" does not allow leading zeros, so consider 1000 - 9999. If repetition is allowed, then every number ending with either 0 or 5 is divisible by five. There are 9000 values and 2 out of 10 (or 1 out of 5) of them are divisible by 5, so 9000/5 = 1800 are divisible by 5 -- if repetition is allowed.

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  • Réponse publiée par: elaineeee

    ANSWER:The first 4-digit number divisible by 11 is 1001.

    EXPLANATION: This is sometimes also referred to as the smallest four digit number divisible by 11 or the lowest 4-digit number divisible by 11. What is the last four digit number divisible by 11? The last 4-digit number divisible by 11 is 9999.

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The four-digit number a55b is divisible by 6 without remainder. what is a and b? ​...