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Solving equations that are transformable in
to quadratic equation

Answers

  • Réponse publiée par: kuanjunjunkuan

    152415641

    3212

    Step-by-step explanation:⊂

  • Réponse publiée par: shannel99

    1.5y-1

    2.3(x+1)

    3.2(x+2)

    Step-by-step explanation:

    HOPE HELP

  • Réponse publiée par: 123gra

    1

    Step-by-step explanation:

    since

    \frac{5y - 1}{2}  = 3y \\

    by cross multiplication

    we have

    5y - 1 = 3y(2)

    5y - 1 = 6y

    equate by 0

    5y - 1 - 6y = 0

    - y - 1 = 0

    and it is not quadratic equation. It is a linear equation

  • Réponse publiée par: cbohol56

    answer:

    ang hirap naman nyan men haha

    Step-by-step explanation:

    kaya mo na yan

  • Réponse publiée par: snow01

    patingin nk example Ng masagutan ko

  • Réponse publiée par: girly61

    sorry girl im just a gr.7 student.

    Step-by-step explanation:

    6.c

    7.d

    8.c

    9.b

    10.a

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Solving equations that are transformable in to quadratic equation...