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The perimeter of a rectangle is 48 feet. if the length is thrice its width, find the dimensions of tge rectangle

Answers

  • Réponse publiée par: elishakim80

    dimension is 6×18 feet

    48 = 2L + 2W

    L = 3W

    therefore;

    48= 2(3W) + 2W

    48= 6W + 2W

    48= 8W

    W= 6

    and

    L = 3W

    L= 3(6)

    L= 18

    to prove :

    48= 2(18) + 2(6)

    48= 36+ 12

    48=48

  • Réponse publiée par: kurtiee
    18 ft × 6 ft

    Step-by-step explanation:

    Let x be the width and 3x the length.

    Getting the width.

    P = 2L × 2W

    48 = 2(3x) + 2(x) \\ 48 = 6x + 2x \\ 48 = 8x \\  \frac{48}{8}  =  \frac{8x}{8}  \\ 6 = x

    Getting the length.

    3x = 3(6) = 18

    Check:

    P = 2L + 2W

    48 = 2(18) + 2(6 \\ 48 = 36 + 12 \\ 48 = 48

    Correct!

  • Réponse publiée par: kelly072

    answer:

    0 is the probability of getting an 8

    explanation:

    you know a die has 6 faces meaning that the set of all possible outcomes that can be obtain from a die is {1,2,3,4,5,6}

    by getting tge probability of obtaining an 8 is impossible because there is no "8" in a die

  • Réponse publiée par: lhadyclaire

    answer: 30yy

    step-by-step explanation: basta

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The perimeter of a rectangle is 48 feet. if the length is thrice its width, find the dimensions of t...