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Give a polynomial equations with integer coefficient

1) 3,4,1
2)4+_2,-1
3)-1,3,-6
4)+_2,+_7
5)0,-4,-5+-9

Answers

  • Réponse publiée par: hellcrack777

    -6,-1,3

    Step-by-step explanation:

    sana makatulonh

    -6,-1,3.

  • Réponse publiée par: batopusong81

    1. . {-2.3.-4}

    since eto ung roots meaning...

    x =  - 2 \\ x = 3 \\ x =  - 4

    transpose mo lahat...

    x  + 2 \\ x - 3 \\x +  4

    (x + 2)(x - 3)( x + 4)

    multiply using foil method.

    ({x}^{2}  - x - 6)(x + 4)

    multiply ulit

    {x}^{3}  -  {x}^{2}  - 6x + 4 {x}^{2}  - 4x - 24

    combine like terms

    {x}^{3}  + 3 {x}^{2}  - 10x - 24

    2. (-1,3.-6.0)

    same solutions

    x =  - 1 \\ x = 3 \\ x =  - 6 \\ x = 0

    magiging..

    x + 1 \\ x - 3 \\ x + 6 \\ x + 0

    (x + 1)(x - 3)(x + 6)(x + 0)

    ({x}^{2}  - 2x - 3)(x + 6)(x + 0)

    ( {x}^{3}   + 4 {x}^{2}  - 15x - 18)(x + 0)

    {x}^{4}  + 4 {x}^{3}  - 15 {x}^{2}  - 18x

    3. {0.2.-3.-1}

    x = 0 \\x = 2 \\  x  =  - 3 \\ x  =  - 1

    x +  0 \\x - 2 \\  x   +  3 \\ x  +  1

    (x +  0)(x - 2)(  x   +  3)( x  +  1)

    ({x}^{2}  - 2x)(  x   +  3)( x  +  1)

    ( {x}^{3}  +  {x}^{2}  - 6x)(x + 1)

    {x}^{4}  + 2 {x}^{3}  - 5 {x}^{2}  - 6x

    4. (-5.-3.0.1}

    x = -5 \\ x = -3 \\ x = 0 \\ x = 1

    x + 5 \\ x  + 3 \\ x  +  0 \\ x  -  1

    (x + 5 )( x  + 3)(x  +  0)( x  -  1)

    ( {x}^{2} + 8x + 15) (x  +  0)( x  -  1)

    ( {x}^{3}  + 8 {x}^{2}  + 15x)(x  -  1)

    {x}^{4}  + 9 {x}^{3}  + 23 {x}^{2}  + 15x

  • Réponse publiée par: hannahleigh

    \large{\mathcal{SOLUTION}}

    Make the roots in linear factors: +2 and +7

    x = 2 , x -2 = 0x = 7 , x - 7 = 0

    Then multiply the linear factors to get the polynomial equation:

    (x-2)(x-7) = 0(x²-7x-2x+14)=0x²-9x+14 = 0

    \\

    \large{\mathcal{ANSWER:}}

    x²-9x+14 = 0
  • Réponse publiée par: JUMAIRAHtheOTAKU

    answer:

    di ko po alam eh ...

    better luck next time po

  • Réponse publiée par: meteor13

    x³ + 4x² - 15x - 18

    Step-by-step explanation:

    x = - 1 ; x + 1

    x = 3 ; x - 3

    x = - 6 ; x + 6

    (x + 1) (x - 3)

    x² - 3x

    + x - 3

    x² - 2x - 3

    (x² - 2x - 3) (x + 6)

    x³ - 2x² - 3x

    6x² - 12x - 18

    x³ + 4x² - 15x - 18

  • Réponse publiée par: cbohol56
    answer:x² - 9x + 14 = 0

    (x-2)(x-7) = 0

    (x²-7x-2x+14)=0

    x²- 9x+14 = 0

    #Better with
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Give a polynomial equations with integer coefficient 1) 3,4,12)4+_2,-13)-1,3,-64)+_2,+_75)0,-4,-5+-9...