# Please help me answer this, how to find area of the shaded region of a circle.

Answers: 1

## Answers

Please help me answer this, how to find area of the shaded region of a circle....

Answers: 1

Please help me answer this, how to find area of the shaded region of a circle....

answer with Step-by-step explanation:

θ = central angle in degrees

r = radius

π = pi = 3.14

4.)

Area of segment (the shaded area)=(θπ/360- sinθ/2) r²

Area of sector = ((100(3.14))/360- sin(100)/2) (5 cm)²

Area of sector = (0.872- 0.985/2)(25 cm² )

Area of segment (shaded) = 9.475 cm²5.)

Area of 3 segments (the shaded area)=3[(θπ/360- sinθ/2) r²]

Where:

θ = 360/3 = 120°

Area = 3[((120(3.14))/360- (sin(120))/2)(6 cm² ]

Area = 3[((376.8))/360- 0.866/2) (36 cm²) ]

Total area of the segments = 66.312 cm²6.)

Shaded region=Area of circle-Area of 5 sectors

Where:

Central angle θ = 360/5 = 72°

Shaded region = πr² - 5[(72(3.14)/360- sin(72)/2) (4 cm)²]

Shaded region = (3.14)(4 cm²) - 5 [(0.628- 0.476)(16 cm²)]

Shaded region = 50.24 cm² - 5[2.432 cm²]

Shaded region = 50.24 cm² - 12.16 cm²

Shaded region (pentagon) = 38.08 cm²(Please click the image below to view the my complete solution.)

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In the figure u can create 5 triangles

Area of triangle is bh/2; b is base and h is the heighr.

In the figure, base is 2 and height is 2 times square root of 3 or 3.464

A of triangle = (2)(3.464)/2

A = 3.464

Area of pentagon = 5 × Area of triangle

= 5×3.464

= 17.32 is my answer.

note: I am not sure of my answer. Bale hinahati ko lang yung figure sa limang triangle to get the Area of pentagon.