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Write 3 780 as a product of its prime factors using exponents.
(with solution please! )​

Answers

  • Réponse publiée par: cleik

    {2}^{2}   \times  {3}^{3}  \times  {5}^{1} \times  {7}^{1} </p<p

    Step-by-step explanation:

    To find the prime factors of 3,780 (or any number) , start by dividing the number by the first prime number, which is 2. If there is no remainder, meaning you can divide evenly, then 2 is a factor of the number. Continue dividing by 2 until you cannot divide evenly anymore. Write down how many 2's you were able to divide by evenly. Now try dividing by the next prime factor, which is 3. The goal is to get to a quotient of 1.


    Write 3 780 as a product of its prime factors using exponents.(with solution please! )​
  • Réponse publiée par: homersoncanceranguiu

    Exponents

    The answer is (2^2)(3^3)(5^1)(7^1).

    Step-by-step explanation:

    To write 3, 780 as a product of its prime factors using exponents, divide 3, 780 by 2 and it will give 1, 890. Divide 1, 890 again by 2 and it will give a quotient of 945. Since 945 is no longer divisible by 2, find another prime number by which it is divisible such that 945 divided by 3 is equals to 315. Divide 315 with the same prime number and it will give 105. 105 divided by the same prime number is equals to 35. Since 35 is no longer divisible by 3, find another prime number thus its factors can be 5 times 7. Writing all the prime factors will give (2)(2)(3)(3)(3)(5)(7) which can be expressed also as (2^2)(3^3)(5^1)(7^1).

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Write 3 780 as a product of its prime factors using exponents.(with solution please! )​...