How to solve direct square variation

Answers

  • Réponse publiée par: ian2145

    For direct square variation, use the equation/formula y = kx, where k is the constant of proportionality. For inverse variation, use the equation y = k/x, again, with k as the constant of proportionality. Remember that these problems might use the word 'proportion' instead of 'variation,' but it means the same thing.

  • Réponse publiée par: HaHannah

    A = π r2. In the language of variation: the area A varies directly with the square of the radius r. ...and the constant of variation is k = π. This formula is an example of "direct" variation."Direct variation" means that, in the one term of the formula, the variable is "on top".

  • Réponse publiée par: nelspas422

    Direct square variation problems are solved using the equation y = kx. In this case, you should use c and d instead of x and y and notice how the word “square root” changes the equation. Step 2: Use the information given in the problem to find the value of k. In this case, you need to find k when c = 6 and d = 256.

  • Réponse publiée par: stacy05

    Direct variation :
    Question :
    y varies directly to x
    y=kx
    k is the constant
    Inverse variation
    Given: y=9
    x=3
    Formula; k=y÷x
    Sol: k= 9÷3
    k=3

    Joint variation
    F varies jointly as x and y
    F=kxy

  • Réponse publiée par: 09389706948

    In the language of variation: the area A varies directly with the square of the radius r. ...and the constant of variation is k = π. This formula is an example of "direct" variation. "Direct variation" means that, in the one term of the formula, the variable is "on top”.

  • Réponse publiée par: reyquicoy4321
    answer:

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  • Réponse publiée par: hannahleigh
    area of a square
    A = s^{2}
    when s = 4cm, A = 16cm^{2}
    when s = 8cm, A = 64cm^{2}
    * When s was increased by 2cm, the increase in area was 2^{2} or 4 times

    area of a circle
    A = π r^{2} 
    when r = 4cm, A = 50.27cm^{2}
    when r = 8cm, A = 201.06cm^{2}
    * When s was increased by 2cm, the increase in area was 2^{2} or 4 times
  • Réponse publiée par: janalynmae
    Direct variation is simply a varies directly to x (a=kx). while direct squared variation is a varies directly to the square of it (a= kx^2).  
  • Réponse publiée par: ShairaGailSanchez
    Direct variation problems are solved using the equation y = kx.; Find the value of k, this is usually a constant variation or proportionality; Redo the equation substituting the value of k; Follow through on the equation and add the remaining information, if this is a word problem remember to include units in the final answer
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How to solve direct square variation...