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Solve the following carefully, then write the correct answer on the space provided before each number in your notebook. 2. choosing a month from a year, what is the probability of selecting a month with 31 days?

Answers

  • Réponse publiée par: kimashleybartolome

      The probability of choosing a 31-day month is 7/12. :)

  • Réponse publiée par: nelspas422

    7/12

    Step-by-step explanation:

    out of 12 months in a year, 7 months have 31 days therefore:

    7/12 is the answer

  • Réponse publiée par: elaineeee

    The probability is 58.3 percent

  • Réponse publiée par: kurtiee

    The probability of choosing a month with 31 days is \frac{7}{12} or 58.33\%.

    The concept of classical probability can be used to solve the given situation.

    The probability of an even to happen is computed by dividing the total considered outcomes by total possible outcomes.

    List of the months with the corresponding days.

    1. January  - 31 days

    2. February - 28 days or 29 days for Leap Year

    3. March - 31 days

    4. April - 30 days

    5. May - 31 days

    6. June - 30 days

    7. July - 31 days

    8. August - 31 days

    9. September - 30 days

    10. October - 31 days

    11. November - 30 days

    12. December - 31 days

    Let say the event, E, is the probability of selecting a month with 31 days.

                            P(E)=\frac{\text{number of months with 31 days}}{\text{total number of months in a year}}.

    There are 7 months which have 31 days and there are 12 months in a year, so the desired probability is the ratio of 31 to 12 or \frac{7}{12}.

                                                    \begin{aligned}P(E)&=\frac{7}{12}\\&=0.5833\\&\text{or}\\&=58.33\%\end{aligned}

    Thus, the answer is 58.33%.

    To learn about the definition of probability, access the link

    To learn how to convert decimal to fraction, go to

    To learn about probability in statistics, click

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Solve the following carefully, then write the correct answer on the space provided before each numbe...