Find the area of a triangle with a base of 8 cm and a height of 7 cm.

Answers

• Réponse publiée par: hajuyanadoy

  AREA OF TRIANGLE

  Find the area of a triangle with a base of 8 cm and a height of 7 cm.

  SOLUTION:base (b) - 8 cmheight (h) - 7 cm

  Area

  A = (1/2) × b × h

  = 1/2 × 56

  = 28 cm²

  ANSWER:

  So, the area of triangle is 28 cm².

  ❤
• Réponse publiée par: meteor13

  The number of element example 1234
• Réponse publiée par: snow01

  Given:
  vi=80 gal
  cin=2 lb/gal
  qin=2 gal/min
  qout=2 gal/min
  (since qin=qout, the volume is constant)
  assume xo(original amount)=0
  cout=x/v=x/80
  
  dx/dt=cinqin-coutqout
  
  dx/dt=(2)(/80)(2)
  
  dx/dt=2[(160-x)/80]
  
  dx/dt=(160-x)/40 (separable de)
  
  dx/(160-x)=dt/40 (integrate)
  
  -ln(160-x)=(1/40)t+c (general solution)
  
  initial condition: xo=0,t=0
  -ln(160-0)=(1/40)(0)+c
  c=-ln(160)=-5.0752
  
  -ln(160-x)=(1/40)t-5.0752 (particular solution)
  
  a.) x at any time t x(t)
  
  -ln(160-x)=(1/40)t-5.0752
  
  ln[(160-x)^-1]=(0.025)t-5.0752
  
  e^{ln[(160-x)^-1]}=e^(0.025t-5.0752)
  
  (160-x)^-1=e^(0.025t-5.0752)
  
  1/(160-x)=e^(0.025t-5.0752) (isolate x)
  
  1/[e^(0.025t-5.0752)]=160-x
  
  x(t)=160-{1/[e^(0.025t-5.0752)]}
  
  b. if c=1 lb/gal, t=?
  
  from c=x/v
  
  1=x/80
  x=80
  
  -ln(160-x)=0.025t-5.0752
  
  -ln(160-80)=0.025t-5.0752
  -ln(80)=0.025t-5.0752
  
  0.025t=5.0752-ln(80)
  
  0.025t=0.6932
  
  t=27.728 mins