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Find the area of a triangle with a base of 8 cm and a height of 7 cm.

Answers

  • Réponse publiée par: hajuyanadoy
    AREA OF TRIANGLE

    Find the area of a triangle with a base of 8 cm and a height of 7 cm.

    SOLUTION:base (b) - 8 cmheight (h) - 7 cm

    Area

    A = (1/2) × b × h

    = 1/2 × 56

    = 28 cm²

    ANSWER:

    So, the area of triangle is 28 cm².

  • Réponse publiée par: meteor13
    The number of element example 1234
  • Réponse publiée par: snow01
    Given:
    vi=80 gal
    cin=2 lb/gal
    qin=2 gal/min
    qout=2 gal/min
    (since qin=qout, the volume is constant)
    assume xo(original amount)=0
    cout=x/v=x/80

    dx/dt=cinqin-coutqout

    dx/dt=(2)(/80)(2)

    dx/dt=2[(160-x)/80]

    dx/dt=(160-x)/40 (separable de)

    dx/(160-x)=dt/40 (integrate)

    -ln(160-x)=(1/40)t+c (general solution)

    initial condition: xo=0,t=0
    -ln(160-0)=(1/40)(0)+c
    c=-ln(160)=-5.0752

    -ln(160-x)=(1/40)t-5.0752 (particular solution)

    a.) x at any time t x(t)

    -ln(160-x)=(1/40)t-5.0752

    ln[(160-x)^-1]=(0.025)t-5.0752

    e^{ln[(160-x)^-1]}=e^(0.025t-5.0752)

    (160-x)^-1=e^(0.025t-5.0752)

    1/(160-x)=e^(0.025t-5.0752) (isolate x)

    1/[e^(0.025t-5.0752)]=160-x

    x(t)=160-{1/[e^(0.025t-5.0752)]}

    b. if c=1 lb/gal, t=?

    from c=x/v

    1=x/80
    x=80

    -ln(160-x)=0.025t-5.0752

    -ln(160-80)=0.025t-5.0752
    -ln(80)=0.025t-5.0752

    0.025t=5.0752-ln(80)

    0.025t=0.6932

    t=27.728 mins
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Find the area of a triangle with a base of 8 cm and a height of 7 cm....