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# Aprojectile is fired horizontally from a gun that is 45.0 m above flat ground, emerging from the gun with a speed of 250 m/s. calculate the amount of time taken by the projectile in the air.

• Réponse publiée par: ian2145

Given:

Yf = 0

Yi= 45 m

Vi = 0

A = 9.8 m/s

t=?

To calculate the amount time taken by the projectile in the air, we use this formula:

Yf-Yi = vit + 1/2at²

Let us substitute:

0 - 45 = 0 - ½ 9.8 t²

45 = 9.8t²/2

2 (45) =9.8 t²

2 (45) /9.8 =t²

t = √2(45)/9.8

= 3s

Other questions related to this are the following:

• Réponse publiée par: cleik

Use the formula (0 - V) / -32.2 ft/s^2 = T

(where V is the initial vertical velocity found in step 2)

For example, if your initial vertical velocity was 32.14 ft/s, it would take 0.998 seconds.

The unit of ft/s^2 denotes feet per second squared.

• Réponse publiée par: elaineeee

Explanation:

Determine the time it takes for the projectile to reach its maximum height. Use the formula (0 - V) / -32.2 ft/s^2 = T where V is the initial vertical velocity found in step 2. ... For example, if your initial vertical velocity was 32.14 ft/s, it would take 0.998 seconds. The unit of ft/s^2 denotes feet per second squared.

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Aprojectile is fired horizontally from a gun that is 45.0 m above flat ground, emerging from the gun...