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A10 kg object resting on a horizontal frictionless surface is subjected to two forces. f1= 30n directed east and f2= 50n directed west. find (a.) acceration; and (b.) displacement after 10 seconds starting from rest.​

Answers

  • Réponse publiée par: molinamaureen080693

    As a plate A continues to move downwards to the mantle, The leading edge of plate A will melt and forms into a magma. Magma rise up to the surface to form a volcanoes..

  • Réponse publiée par: taekookislifeu

    Explanation:

    1force

    noun\ˈfȯrs\

    : physical strength, power, or effect

    : power or violence used on a person or thing

    : strength or power that is not physical

  • Réponse publiée par: nelgelinagudo

    Hello!

    A car travels 35.0 mph north for 1.00 hour, then 40.0 mph east for 0.0500 hour, and finally 50.0 mph northeast for 2.00 hours. Calculate the average speed. v = mph

    We have the following data:

    * velocity (in mph)

    (V1) = 35.0 mph

    (V2) = 40.0 mph

    (V3) = 50.0 mph

    * weights for the time (in hours)

    (T1) = 1.00 hour

    (T2) = 0.0500 hour

    (T3) = 2.00 hours

    We apply the data to the weighted average formula to find the average speed, let us see:

    Weight\:Average = \dfrac{V_1*T_1+V_2*T_2+V_3*T_3}{T_1+T_2+T_3}

    Weight\:Average = \dfrac{35.0*1.00+40.0*0.0500+50.0*2.00}{1.00+0.0500+2.00}

    Weight\:Average = \dfrac{35+2+100}{3.05}

    Weight\:Average = \dfrac{137}{3.05}

    Weight\:Average = 44.91803279...

    \boxed{\boxed{Weight\:Average = 44.92\:mph}}\Longleftarrow(Average\:Speed)\:\:\:\:\:\:\bf\purple{\checkmark}

    The Average Speed is approximately 44.92 mph

    _______________________

    \bf\purple{I\:Hope\:this\:helps,\:greetings ...\:Dexteright02!}\:\:\ddot{\smile}

  • Réponse publiée par: snow01

    Good Day

    Problem:

    You drop your cellphone while in the bathroom in front of the mirror while the water is running is in the sink below. If you are 0.45meters above the sink,how long do you have before your cell phone is a gonner.

    Given Data:

    Vi (initial velocity)  =  0 m/s (at top)

    d (distance) = 0.45 m

    t (time) =  unknown

    a (acceleration) = 9.8 m/s²

    Solution:

    We can use the formula  t = √d/1/2a  since Vi = 0 m/s

     t = √d/1/2a

       = √ 0.45 m / 1/2(9.8 m/s²)

    )

       = √ 0.45 m / 4.9 m/s²

       = √0.0918 s²

       = 0.303 s

    You have  0.303 seconds or 0.30 seconds or 0.3 seconds

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A10 kg object resting on a horizontal frictionless surface is subjected to two forces. f1= 30n direc...