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# A20 n box is being dragged with constant velocity along a horizontal surface of the table by a rope that is at an angle of 30 degrees with that surface. the tension in the rope is 5 n. what is the coefficient of friction?

Given:

W= 20 N

angle= 30°

exerted force= 5N

Formula:

Normal Force= W – exerted force sin 30°

Solution:

Normal Force= 20 N – 5 N sin 30°

Normal Force= 20 N – 5 N (0.5)

Normal Force= 20 N – 2.5 N

Normal Force= 17.5 N

• Réponse publiée par: enrica11
C, because its the only answer i know
• Réponse publiée par: nelspas422

Calculating the displacement of a fault

1)μ is the shear modulus of the rocks involved in the earthquake (in Pa)

2)A is the area of the rupture along the geologic fault where the earthquake occurred (in m2), and.

3)D is the average displacement on A (in m).

Explanation:

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A20 n box is being dragged with constant velocity along a horizontal surface of the table by a rope...