W= 20 N
exerted force= 5N
Normal Force= W – exerted force sin 30°
Normal Force= 20 N – 5 N sin 30°
Normal Force= 20 N – 5 N (0.5)
Normal Force= 20 N – 2.5 N
Normal Force= 17.5 N
Calculating the displacement of a fault
1)μ is the shear modulus of the rocks involved in the earthquake (in Pa)
2)A is the area of the rupture along the geologic fault where the earthquake occurred (in m2), and.
3)D is the average displacement on A (in m).