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# How many kg of ferric oxide can be obtained by roasting 5kg of ferrous sulfide​

Answers: 3

## Answers

• Réponse publiée par: aimeedelacruz24
T=cos data(one angle)/cos data(another angle) im not but thats how we compute when we are searching for tension 2 in one problem in college physics
• Réponse publiée par: saintjohn

B

Explanation:

Because if we will mental it... Think The ball a is thrown upward even it can pull downward by the gravity ball b is the fastest because the ball b has already force to hit the ground and when the gravity pull it the force that has the ball b much be faster than its original force

Sorry, if you dont understand ask

me I'm glad to help you thanks

--Amira

• Réponse publiée par: jemuelpogi

Hello!

A pitcher claims he can throw a 0.151 kg  baseball with as much momentum as a 3.04 g bullet moving with a speed of 14042 m/s.  What must be its speed if the pitcher’s  claim is valid?  answer in units of m/s.

We have the following data:

m' (mass pitcher) = 0.151 kg

v' (velocity pitcher) = ? (in m/s)

m'' (mass bullet) = 3.04 g → 0.00304 kg

v'' (velocity bullet) = 14042 m/s

Applying the formula of momentum which is p = m*v

p' (momentum baseball) = p'' (momentum ballet)

Note:

I want to make it clear, to this day it is practically impossible for a baseball player to reach a certain speed in his pitch, knowing that the Guiness record indicates that Aroldis Chapman reached 168.9 km / h, that is, about 46.9 m / s . So the solution to the question answered above is correct, although the data in the statement does not match (or question with poorly formulated data). Therefore, the pitcher’s  claim is not valid !

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How many kg of ferric oxide can be obtained by roasting 5kg of ferrous sulfide​...