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Explain equation of states and cross coupled properties

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  • Réponse publiée par: alexespinosa

    The average velocity is 8 km/hr

    Further explanation

    This problem is about Average Velocity.

    Given:

    The first displacement = d₁ = 10 km

    Initial velocity = v₁ = 10 km/hr

    The second displacement = d₂ = 2 km

    Time taken for second displacement = t₂ = 30 mins = ¹/₂ hr

    Asked:

    Average velocity = v = ?

    Formula:

    \boxed{\texttt{Average Velocity } = \texttt{Total Displacement} \div \texttt{Total Time Taken}}

    Solution:

    Firstly, we calculate the time taken for the first displacement:

    t_1 = d_1 \div v_1

    t_1 = 10 \div 10

    t_1 = 1 \texttt{ hr}

    \texttt{ }

    Next, we could calculate the average velocity:

    \texttt{Average Velocity } = \texttt{Total Displacement} \div \texttt{Total Time Taken}

    v = \frac{d_1 + d_2}{t_1 + t_2}

    v = \frac{10 + 2}{1 + \frac{1}{2}}

    v = \frac{12}{\frac{3}{2}}

    v = 12 \times \frac{2}{3}

    v = 8 \texttt{ km/hr}

    \texttt{ }

    The average velocity is 8 km/hr

    \texttt{ }

    Learn moreKinetic Energy : Velocity of The Ball : Vectors of Displacement : answer details

    Grade: High School

    Subject: Physics

    Chapter: Kinematics

    Keywords: Velocity , Driver , Car , Deceleration , Acceleration , Obstacle , Projectile , Motion , Horizontal , Vertical , Release , Point , Ball , Wall


    You are driving an old truck along a straight road for 10km at 10km/hr. at this point, you ran out o
  • Réponse publiée par: batopusong81

    Rest

    Explaination:

    Rest is a state in physics that refers to an object being stationary relative to a particular frame of reference or another object; when the position of a body with respect to its surroundings does not change with time it is said to be "at rest".

  • Réponse publiée par: villatura

    Good Day

    Problem:

    Upton Chuck is riding the giant drop at Great America. If Upton free falls for 2.60 seconds, what will be his final velocity and how far will he fall?

    Given Data:

    Vi (initial velocity)  =  0 m/s (at top)

    Vf (final velocity) = unknown

    t (time) =  2.60 seconds

    a (acceleration) = 9.8 m/s²

    Solution:

    a= Vf-Vi/t, to solve Vf, we can use  Vf = at +Vi

    Vf = at +Vi

        = 9.8 m/s² × 2.60 s + 0 m/s

        = 25.48 m/s + 0 m/s

        = 25.48 m/s

    Solving for distance:

    d = (Vf + Vi) / 2 × t

      = 25.48 m/s / 2 × 2.60 s

      = 33.124 m

    Final velocity is  25.48 m/s

    Distance = 33.124 m

  • Réponse publiée par: kambalpandesal23
    Given:
    3N = Newton
    1.5 kg = Mass

    Asked:
    Acceleration = ?

    Formula:
    Acceleration = Force/Mass

    Solution:
    Acceleration = 3N/1.5kg
    Acceleration = 2m/s^2

    Final
    The acceleration is 2 m/s^2.
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Explain equation of states and cross coupled properties...