Bernoulli's principle states that a1v1=a2v2. blood flows from artery a1, whose cross-sectional area is 50 u2, at a velocity of 5mm/s to its more peripheral branches, a2, a3, a4, and a5. if the total cross-sectional area of the branches is 250 u2 and each branch has exactly the same diametr as the other, what is the velocity of blood in the branches?
Answers: 3
Vf - Vi
a =
t
Explanation:
vf - final velocity
vi - initial position
t - time
The net force would be 5 because 10-5 = 5 and yes the object will move where the higher units have.
#JuneChallenge
Explanation:
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Problem:
Akieya is playing with a ball on top of a building but the ball fell and hits the squad after 1.9 second.What is the final velocity of the ball just before it hits the ground? How tall is the building?
Given Data:
a (acceleration) = 9.8 m/s²
t (time) = 1.9 s
Vi (initial velocity) = 0 m/s
Vf (final velocity) = ? unknown
Solution:
We can use the formula, a = (Vf - Vi)/t
To find Vf, Vf = at + Vi
Vf = at + Vi
= 9.8 m/s² × 1.9 s + 0 m/s
= 18.62 m/s + 0 m/s
= 18.62 m/s
Final velocity 18.62 m/s
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