A plane bound for Kuala Lumpur accelerates on a runaway from rest to 3.22m/s² within 32.0s until it finally takes off. Find the distance traveled before takeoff. Use GRFS to solve.
a (acceleration) = 3.22m/s²
t (time) = 32.0 seconds
Vi (initial velocity) = 0 m/s (from rest)
d (distance) = unknown ?
We can use the formula d = Vit + 1/2at²
Since Vi = 0 m/s, we will just used d = 1/2at²
d = 1/2at²
= 1/2 × 3.22m/s² × (32.0 s)²
= 1.61 m/s² × 1024 s² (cancel the unit s²)
= 1648.64 m
the distance traveled before takeoff is 1648.64 m
Cause the Earth circulates around us very slowly
I hoped it work