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Accomplished silver workers in India can pound silver into incredibly thin sheets, as thin as 3.00 x 10-7 m (about one-hundredth of the thickness of this sheet of paper). Find the area of such a sheet that can be formed from 1.00 kg of silver.

Answers

  • Réponse publiée par: maledabacuetes

    p = density

    m = mass

    V = volume

    V=m/p

    p=m/V

    m=pV

  • Réponse publiée par: nila93

    Hello!

    A car starts from rest and accelerates uniformly over a time of 5.21 seconds for a distance of 110 m. Determine the acceleration of the car ?

    We have the following data:

    Vi (initial velocity) = 0 m/s

    t (time) = 5.21 s

    a (average acceleration) = ? (in m/s²)

    d (distance interval) = 110 m

    By the formula of the space of the Uniformly Varied Movement, it is:

    d = v_i * t + \dfrac{a*t^{2}}{2}

    110 = 0 * 5.21 + \dfrac{a*(5.21)^{2}}{2}

    110 = 0 + \dfrac{a*27.1441}{2}

    110 = \dfrac{27.1441\:a}{2}

    27.1441\:a = 110*2

    27.1441\:a = 220

    a = \dfrac{220}{27.1441}

    \boxed{\boxed{a \approx 8.1\:m/s^2}}\longleftarrow(acceleration)\:\:\:\:\:\:\bf\blue{\checkmark}\bf\green{\checkmark}\bf\red{\checkmark}

    The acceleration of the car is approximately 8.1 m/s².

    ________________________________  

    \bf\red{I\:Hope\:this\:helps,\:greetings ...\:Dexteright02!}

  • Réponse publiée par: kimashleybartolome

    Hello!

    Polar bears can swim approximately 25 km in 3 h. How long would it take them to swim 15 m ?​

    We have the following data:

    25 km = 25000 m

    3 h = 3*(60min) = 180 min = 180*(60s) = 10800 s

    Solving: Rule of three (directly proportional)

    distance (m) ______ time (s)

    25000 -------------------- 10800 s

    15 -------------------------- y

    \dfrac{25000}{15} = \dfrac{10800}{y}

    multiply the means by the extremes

    25000*y = 15*10800

    25000\:y = 162000

    y = \dfrac{162000\!\!\!\!\!\!\!\!\!\dfrac{\hspace{0.5cm}}{~}}{25000\!\!\!\!\!\!\!\!\!\dfrac{\hspace{0.5cm}}{~}}

    y = \dfrac{162}{25}

    y = 6.48\:s \to \boxed{\boxed{y \approx 6.5\:seconds}}\:\:\:\:\:\:\bf\green{\checkmark}

    Polar bears would take about 6.5 seconds to swim for 15 m.

    #JuneChallenge

    #answerchallenge

    ________________________

    \bf\pink{I\:Hope\:this\:helps,\:greetings ...\:Dexteright02!}\:\:\ddot{\smile}

  • Réponse publiée par: 20201947

    Good Day

    Problem:

    a flower falls from a windowsill 9.2 meters above the sidewalk.

    1. How fast is the flower pot moving when it strikes the ground?

    Given Data:

    a (acceleration) = 9.8 m/s²

    d (distance) = 9.2 m

    Vf (final velocity) = ? unknown

    Vi (initial velocity) = 0 m/s

    Solution:

    We can use the formula Vf = √2ad

    Vf = √2ad

        = √2 × 9.8 m/s²  × 9.2 m

       = √180.32 m²/s²

        = 13.43 m/s

    13.43 m/s

    2. How much time will it take for the flowerpot to hit the ground?

    Given Data:

    a (acceleration) = 9.8 m/s²

    Vf (final velocity) = 13.43 m/s

    Vi (initial velocity) = 0 m/s

    t (time) = ? unknown

    Solution:

    we use the formula t = Vf-Vi/a

    t = Vf-Vi/a

     = (13.43 m/s - 0 m/s)/ 9.8 m/s²

      = 13.43 m/s  / 9.8 m/s²

      =  1.37 seconds

    1.37 seconds

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Accomplished silver workers in India can pound silver into incredibly thin sheets, as thin as 3.00 x...