# Accomplished silver workers in India can pound silver into incredibly thin sheets, as thin as 3.00 x 10-7 m (about one-hundredth of the thickness of this sheet of paper). Find the area of such a sheet that can be formed from 1.00 kg of silver.

Answers: 1

## Answers

Accomplished silver workers in India can pound silver into incredibly thin sheets, as thin as 3.00 x...

p = density

m = mass

V = volume

V=m/p

p=m/V

m=pV

Hello!

A car starts from rest and accelerates uniformly over a time of 5.21 seconds for a distance of 110 m. Determine the acceleration of the car ?

We have the following data:

Vi (initial velocity) = 0 m/s

t (time) = 5.21 s

a (average acceleration) = ? (in m/s²)

d (distance interval) = 110 m

By the formula of the space of the Uniformly Varied Movement, it is:

The acceleration of the car is approximately 8.1 m/s².

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Hello!

Polar bears can swim approximately 25 km in 3 h. How long would it take them to swim 15 m ?

We have the following data:

25 km = 25000 m

3 h = 3*(60min) = 180 min = 180*(60s) = 10800 s

Solving: Rule of three (directly proportional)

distance (m) ______ time (s)

25000 -------------------- 10800 s

15 -------------------------- y

multiply the means by the extremes

Polar bears would take about 6.5 seconds to swim for 15 m.

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Good Day

Problem:

a flower falls from a windowsill 9.2 meters above the sidewalk.

1. How fast is the flower pot moving when it strikes the ground?

Given Data:

a (acceleration) = 9.8 m/s²

d (distance) = 9.2 m

Vf (final velocity) = ? unknown

Vi (initial velocity) = 0 m/s

Solution:

We can use the formula Vf = √2ad

Vf = √2ad

= √2 × 9.8 m/s² × 9.2 m

= √180.32 m²/s²

= 13.43 m/s

13.43 m/s

2. How much time will it take for the flowerpot to hit the ground?

Given Data:

a (acceleration) = 9.8 m/s²

Vf (final velocity) = 13.43 m/s

Vi (initial velocity) = 0 m/s

t (time) = ? unknown

Solution:

we use the formula t = Vf-Vi/a

t = Vf-Vi/a

= (13.43 m/s - 0 m/s)/ 9.8 m/s²

= 13.43 m/s / 9.8 m/s²

= 1.37 seconds

1.37 seconds