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Acontainer is filled with water and the pressure at the container bottom is p. if the container is instead filled with oil having specific gravity 0.80, what new bottom pressure results?

Answers

  • Réponse publiée par: 123gra
    150 gallons/drum  x  12 drums = 1,800 gallons
  • Réponse publiée par: 09330399672

    What kind of question is this?

    No one can answer this

  • Réponse publiée par: nelspas422
    Asked: What fraction of the container is empty?
    Given: 1/3 water , 1/4 water
    Operation: Addition, Subtraction
    Solution: (1/3) + (1/4) = n
    n = (7/12) < we now have a common fraction

    =
    (12/12) - (7/12) = 5/12

    5/12 is the missing fraction of the container
  • Réponse publiée par: JUMAIRAHtheOTAKU
    Just subtract the sum of 1/4 and 1/3 on 1
    .
    1 - [(1/3) + (1/4)]
    Get the least common denominator. LCD = 12
    = 12/12 - [(4/12) + (3/12)]
    = 12/12 - (7/12)
    = 5/12
    .
    Therefore, 5/12 of the tank is empty.
  • Réponse publiée par: calmaaprilgrace
    The answer is 3,250 ΔΔΔΔΔΔΔΔΔΔΔΔΔΔΔΔΔΔΔ
  • Réponse publiée par: kurtiee
    X=be the number of pieces; weight f watrmln=wt. of full cntner-wt.contner; w.wtrmlon=22.1-.5=21.6; x=21.6/1.2; x=18pcs of wtrmlon
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Acontainer is filled with water and the pressure at the container bottom is p. if the container is i...