# Acontainer is filled with water and the pressure at the container bottom is p. if the container is instead filled with oil having specific gravity 0.80, what new bottom pressure results?

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## Answers

Acontainer is filled with water and the pressure at the container bottom is p. if the container is i...

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Given: 1/3 water , 1/4 water

Operation: Addition, Subtraction

Solution: (1/3) + (1/4) = n

n = (7/12) < we now have a common fraction

=

(12/12) - (7/12) = 5/12

5/12 is the missing fraction of the container

.

1 - [(1/3) + (1/4)]

Get the least common denominator. LCD = 12

= 12/12 - [(4/12) + (3/12)]

= 12/12 - (7/12)

= 5/12

.

Therefore, 5/12 of the tank is empty.