# Aforce of 120 n is applied to a 50-kg mass in the direction of motion for a distance of 7.0 m and then the force is increased to 160 n for the next 3.0 m. for the 10 m of travel, how much work is done by the varying force? select one: a. 1 320 j b. 66 000 j c. 26.4 j d. 1 220 j e. 1 480 j

Answers: 3

## Answers

Aforce of 120 n is applied to a 50-kg mass in the direction of motion for a distance of 7.0 m and th...

The answer is a. 1320 J.

Explanation:

The problem is asking for the total work done by the varying force. Work is the product of force and the displacement caused by the force exerted . To get this, we must use the equation:

In this particular problem,

Substituting these values, we get

Note that 1 Nm = 1 J

I hope this helps. :)